Statement

Let GG be a that is , with a fixed . For f,gL1(G)f,g\in L^1(G), define their using that measure. The Fourier convolution theorem states that

fg^(γ)=f^(γ)g^(γ)(γG^),\widehat{f*g}(\gamma)=\widehat f(\gamma)\widehat g(\gamma) \qquad(\gamma\in\widehat G),

where hats denote the on GG and G^\widehat G is the . Thus the Fourier transform is an from the convolution algebra L1(G)L^1(G) to continuous functions on G^\widehat G with pointwise multiplication.

Proof mechanism

Expanding the definitions gives

fg^(γ)=GGf(y)g(y1x)γ(x)dydx.\widehat{f*g}(\gamma) =\int_G\int_G f(y)g(y^{-1}x)\overline{\gamma(x)}\,dy\,dx.

Absolute integrability permits . The substitution x=yzx=yz, left invariance of Haar measure, and γ(yz)=γ(y)γ(z)\gamma(yz)=\gamma(y)\gamma(z) split the double integral into f^(γ)g^(γ)\widehat f(\gamma)\widehat g(\gamma). This calculation also explains exactly where commutativity enters: it makes scalar characters sufficient to diagonalize convolution Folland, Chapter 4.

Analytic consequences

Convolution operators become multiplication operators after Fourier transformation. With the , the therefore converts suitable translation-invariant operators on L2(G)L^2(G) into multiplication by Fourier multipliers. The identity also shows that zeros of Fourier transforms control invertibility and ideal structure in the commutative .

Examples and conventions

For G=RnG=\mathbb R^n, this is the classical identity F(fg)=(Ff)(Fg)\mathcal F(f*g)=(\mathcal Ff)(\mathcal Fg). For G=ZG=\mathbb Z, convolution of sequences becomes multiplication of Fourier series on the circle. Changing the sign or 2π2\pi convention in both transforms leaves the product identity unchanged.

References
  1. W. Rudin, Fourier Analysis on Groups, Wiley-Interscience, 1962. DOI record. Relevant: Fourier transforms and convolution on locally compact abelian groups.
  2. G. B. Folland, A Course in Abstract Harmonic Analysis, 2nd ed., CRC Press, 2016. DOI record. Relevant: Chapter 4, Fourier analysis on locally compact abelian groups.