Definition

Let GG be a , let μ\mu be a left , and let Δ\Delta be its , with Gh(xg)dμ(x)=Δ(g)1Gh(x)dμ(x)\int_G h(xg)\,d\mu(x)=\Delta(g)^{-1}\int_G h(x)\,d\mu(x). For fL1(G,μ)f\in L^1(G,\mu), the convolution involution is

f(x)=Δ(x1)f(x1)f^*(x)=\Delta(x^{-1})\,\overline{f(x^{-1})}

for almost every xGx\in G. Together with (fg)(x)=Gf(y)g(y1x)dμ(y)(f*g)(x)=\int_G f(y)g(y^{-1}x)\,d\mu(y), this operation makes L1(G,μ)L^1(G,\mu) a Banach *-algebra: it is conjugate-linear, (f)=f(f^*)^*=f, (fg)=gf(f*g)^*=g^* * f^*, and f1=f1\lVert f^*\rVert_1=\lVert f\rVert_1.

Why the modular factor is present

Group inversion need not preserve a left Haar measure. The factor Δ(x1)\Delta(x^{-1}) is exactly the Radon–Nikodym correction that compensates for this change of measure. It makes the integrated form of a satisfy π(f)=π(f)\pi(f^*)=\pi(f)^*, where π(f)=Gf(x)π(x)dμ(x)\pi(f)=\int_G f(x)\pi(x)\,d\mu(x). This convention and its compatibility with are developed in Folland, §§2.4 and 3.1.

The unimodular case

If GG is , then Δ=1\Delta=1, so the formula reduces to f(x)=f(x1)f^*(x)=\overline{f(x^{-1})}. Dropping the modular factor on a nonunimodular group generally destroys both the L1L^1-isometry and the adjoint identity for integrated representations.

Conventions and scope
References
  1. Gerald B. Folland, A Course in Abstract Harmonic Analysis, 2nd ed., CRC Press, 2016. DOI record. Relevant: §§2.4 and 3.1 on convolution, involution, and integrated representations.