Let π:P→M\pi:P\to M be a with right action p⋅gp\cdot g, and let FF be a equipped with a smooth left action of the GG.

The associated bundle with fiber FF is the quotient

P×GF:=(P×F)/∼,P\times_G F := (P\times F)/\sim,

where the equivalence relation is

(p⋅g, f)∼(p, g⋅f)(p∈P,  f∈F,  g∈G).(p\cdot g,\, f)\sim (p,\, g\cdot f)\qquad (p\in P,\; f\in F,\; g\in G).

Write [p,f][p,f] for the of (p,f)(p,f). The projection map

πF:P×GF→M,πF([p,f])=π(p)\pi_F:P\times_G F \to M,\qquad \pi_F([p,f])=\pi(p)

is well-defined, and P×GFP\times_G F is a over MM with FF.

Concretely, P×GFP\times_G F is a : it is obtained from the product P×FP\times F by dividing out the diagonal GG-action determined by the right action on PP and the left action on FF. When FF is a with a linear action, this specializes to an .

Structure group

If local sections of PP satisfy sj=sigijs_j=s_i g_{ij}, the induced fiber coordinates on P×GFP\times_G F change by (x,f)↦(x,gij(x)⋅f)(x,f)\mapsto(x,g_{ij}(x)\cdot f). These maps give the associated bundle its structure, with model fiber FF.

Examples
  1. Tangent bundle from frames. If P=Fr(M)P=\mathrm{Fr}(M) and F=RnF=\mathbb{R}^n with the standard left action of GL(n)GL(n), then P×GFP\times_G F is canonically isomorphic to the TMTM.
  2. from U(1)U(1)-bundles. If G=U(1)G=U(1) and F=CF=\mathbb{C} with the usual multiplication action, then P×U(1)CP\times_{U(1)}\mathbb{C} is a complex line bundle whose unit circle bundle recovers PP.
  3. Adjoint bundle. Taking F=GF=G with conjugation action produces the adjoint bundle Ad(P)\mathrm{Ad}(P) (a bundle of groups over MM).