Definition
Even K-theory/K-homology index pairing
The integer obtained by compressing the off-diagonal operator of an even Fredholm module by a K-zero projection.
Definition
Let be a unital complex -algebra, let be a normalized even Fredholm module, and write for its positive-to-negative part. For a projection representing a -class, put . The compression
is Fredholm, and the even index pairing is
It extends additively to differences of projections, giving a bilinear pairing .
Why the compression is Fredholm
Because is compact, has as an inverse modulo compact operators. The compressed operator is therefore Fredholm by Atkinson's characterization. Its index is unchanged under stabilization of , homotopy of the projection, compact perturbation of , and stable homotopy of the Fredholm module. These facts make the formula descend to and analytic K-homology. Connes, Chapter IV, Section 1, Proposition 2(a).
For a class , the value is
This subtraction is essential: the pairing is defined on the Grothendieck group, not only on individual projections.
Geometric example
Let be a closed even-dimensional spin manifold and take the even Fredholm module obtained from its Dirac operator. A projection determines a vector bundle . The compression represents the Dirac operator twisted by , so the pairing is its Fredholm index. This is the operator-theoretic bridge from a -class to an integer index. Connes, Chapter IV, Section 1, example and Proposition 2.
For , pairing the class of a finite-rank projection with an even cycle scales the cycle's basic index by the rank.
Conventions and scope
For nonunital , projections are taken in matrix algebras over the unitization, with the scalar projection subtracted so that the class lies in . An unnormalized Fredholm module may be normalized or handled directly modulo compact operators before compression.
Switching which grading summand is called positive, or replacing the Fredholm-index convention by its negative, reverses the displayed sign. The convention in the core agrees with Connes's Proposition 2(a).