Definition

Let XX and YY be over the same scalar field. A T:XYT:X\to Y is a bounded linear operator if there is a constant C0C\geq0 such that

TxYCxXfor every xX.\lVert Tx\rVert_Y\leq C\lVert x\rVert_X \qquad\text{for every }x\in X.

The least such constant is the

T=supxX1TxY.\lVert T\rVert=\sup_{\lVert x\rVert_X\leq1}\lVert Tx\rVert_Y.

Boundedness here constrains the image of every vector uniformly; it does not mean that the set T(X)T(X) is bounded.

Equivalent continuity conditions

For a linear map between normed spaces, the following are equivalent:

  • it is bounded;
  • it is continuous at 00;
  • it is continuous at every point; and
  • it maps bounded subsets of XX to bounded subsets of YY.

Thus bounded linear operators are precisely the normed-space instances of . The equivalence uses linearity; an arbitrary continuous nonlinear map need not satisfy a global estimate by x\lVert x\rVert.

Operator spaces

The bounded operators from XX to YY form a B(X,Y)B(X,Y) under the operator norm. If YY is a , then B(X,Y)B(X,Y) is Banach, whether or not XX is complete. When X=YX=Y, composition satisfies

STST,\lVert ST\rVert\leq\lVert S\rVert\lVert T\rVert,

so B(X)=B(X,X)B(X)=B(X,X) is a normed algebra and is a when XX is Banach.

Examples and scope

Every linear map between finite-dimensional normed spaces is bounded. The derivative D:C1([0,1])C([0,1])D:C^1([0,1])\to C([0,1]) is bounded when the source carries the C1C^1-norm, but it is not bounded when both spaces are given the . On an infinite-dimensional normed space, discontinuous linear maps can exist; they are everywhere-defined algebraic operators but are not bounded linear operators.

References
  1. John B. Conway, A Course in Functional Analysis, 2nd ed., Graduate Texts in Mathematics 96, Springer, 1990. DOI record. Relevant: Chapter II on normed spaces and bounded operators.
  2. Walter Rudin, Functional Analysis, 2nd ed., McGraw–Hill, 1991. WorldCat record. Relevant: Chapter 4 on continuous linear mappings.