The supremum norm of a bounded function f:XRf:X\to\mathbb{R} is

f=supxXf(x).\|f\|_\infty=\sup_{x\in X} |f(x)|.

Here sup\sup denotes the and |\cdot| is the .

Remarks

The supremum norm is the standard way to measure uniform size of functions and underlies the . On many domains of interest (for example, a closed interval), continuous functions lie in the and are bounded, so \|\cdot\|_\infty is finite.

Examples
  • For f(x)=sinxf(x)=\sin x on R\mathbb{R}, f=1\|f\|_\infty=1.
  • For f(x)=x2f(x)=x^2 on [1,1][-1,1], f=1\|f\|_\infty=1 (the maximum is attained at x=±1x=\pm 1).
Comparison with an essential supremum

If ff is continuous on a space where every nonempty open set has positive measure, then supf=ess supf\sup|f|=\operatorname*{ess\,sup}|f|, including when both are infinite. Indeed, if f(x)>a|f(x)|>a at a point, continuity gives a nonempty open set where f>a|f|>a, so an almost-everywhere bound by aa is impossible. Without continuity or this measure hypothesis, the two notions can differ.