Let UVRnU\subseteq V\subseteq\mathbb R^n be open and f:URmf:U\to\mathbb R^m smooth. A smooth extension of ff to VV is a F:VRmF:V\to\mathbb R^m whose to UU equals ff.

Existence and nonuniqueness

An extension need not exist: 1/t1/t on (0,1)(0,1) has no continuous extension across zero. When one exists it need not be unique, since smooth functions supported in VUV\setminus\overline U may be added without changing the restriction.

The gives a useful sufficient condition across a flat boundary. concerns prescribing boundary derivatives; it does not assert that an arbitrary function on an open domain extends smoothly.