Reverse triangle inequality: In a (V,∥⋅∥)(V,\|\cdot\|), for all u,v∈Vu,v\in V,

∣∥u∥−∥v∥∣≤∥u−v∥.\bigl|\|u\|-\|v\|\bigr|\le \|u-v\|.

Equivalently,

∥u∥≤∥v∥+∥u−v∥and∥v∥≤∥u∥+∥u−v∥.\|u\|\le \|v\|+\|u-v\|\quad\text{and}\quad \|v\|\le \|u\|+\|u-v\|.
Remarks

This inequality is frequently used to show of the norm map and to transfer of vectors to convergence of their norms.

Examples
  • In R\mathbb{R}, the inequality becomes ∣∣a∣−∣b∣∣≤∣a−b∣\bigl||a|-|b|\bigr|\le |a-b|.
  • If un→uu_n\to u in a , then ∥un∥→∥u∥\|u_n\|\to \|u\| by the reverse .