Third isomorphism theorem (rings): Let RR be a ring and let IJI\subseteq J be of RR. Then J/IJ/I is an ideal of R/IR/I, and there is a natural

(R/I)/(J/I)  R/J(R/I)/(J/I)\ \cong\ R/J

of .

Remarks

This formalizes the idea that “modding out in stages” is equivalent to modding out by the total relation.