Let φ:RS\varphi:R\to S be a . Then

ker(φ)={rR:φ(r)=0S}\ker(\varphi)=\{r\in R:\varphi(r)=0_S\}

is a two-sided of RR.

Consequence

One can therefore form the R/kerφR/\ker\varphi. This is the key input for .