Let φ:R→S\varphi:R\to S be a . Then

ker⁡(φ)={r∈R:φ(r)=0S}\ker(\varphi)=\{r\in R:\varphi(r)=0_S\}

is a two-sided of RR.

Consequence

One can therefore form the R/ker⁡φR/\ker\varphi. This is the key input for .