Let GG be a finite group and let kk be an algebraically closed field with char⁡(k)∤∣G∣\operatorname{char}(k)\nmid |G|. Let

{V1,…,Vr}\{V_1,\dots,V_r\}

be a complete set of pairwise non-isomorphic finite-dimensional of GG over kk, and write di=dim⁡k(Vi)d_i=\dim_k(V_i). Then

∑i=1rdi2  =  ∣G∣.\sum_{i=1}^r d_i^2 \;=\; |G|.
Regular-representation form

Equivalently, the underlying kGkG-module of the decomposes as

k[G]  ≅  ⨁i=1rdi Vi,k[G]\;\cong\;\bigoplus_{i=1}^r d_i\,V_i,

and taking dimensions gives dim⁡k(k[G])=∣G∣=∑ididim⁡(Vi)=∑idi2\dim_k(k[G])=|G|=\sum_i d_i\dim(V_i)=\sum_i d_i^2.

This decomposition follows from , which makes k[G]k[G] semisimple, together with multiplicity computations using .

Examples

The characteristic hypothesis holds for k=Ck=\mathbb C, the standard complex-representation setting.

  1. Cyclic group CnC_n. Over C\mathbb C, every irreducible representation of CnC_n is 11-dimensional (a character). There are nn such characters, so
    ∑idi2  =  12+⋯+12⏟n times  =  n  =  ∣Cn∣.\sum_i d_i^2 \;=\; \underbrace{1^2+\cdots+1^2}_{n\text{ times}} \;=\; n \;=\; |C_n|.
  1. Symmetric group S3S_3 (order 66). S3S_3 has irreducible degrees 1,1,21,1,2 (trivial, sign, and the 22-dimensional standard representation), hence
    12+12+22  =  6  =  ∣S3∣.1^2+1^2+2^2 \;=\; 6 \;=\; |S_3|.
  1. Dihedral group D8D_8 (symmetries of a square, order 88). D8D_8 has four 11-dimensional irreducibles and one 22-dimensional irreducible, so
    4⋅12+1⋅22  =  8  =  ∣D8∣.4\cdot 1^2 + 1\cdot 2^2 \;=\; 8 \;=\; |D_8|.