Schur's Lemma
Intertwiners between irreducible representations are either zero or isomorphisms; equivariant endomorphisms form a division algebra (scalars over ℂ).
Let be a group and let be a field. A (finite-dimensional) -representation of is a -vector space with a homomorphism . A -intertwiner (or -map) between two representations is a -linear map satisfying
Equivalent characterizations
Equivalently, is a module homomorphism for -modules, where is the group algebra.
Theorem (Schur's Lemma)
Let be irreducible representations of over . Then:
- Every nonzero -intertwiner is an isomorphism. In particular, if , then .
- The endomorphism ring is a division ring (every nonzero element is invertible).
- If is algebraically closed and is finite-dimensional (e.g. ), then
i.e. every -equivariant endomorphism is scalar multiplication.
Remarks
This result is frequently paired with character theory and the corollary that central elements act by scalars on irreducibles (see Schur's corollary).
Examples
Example 1: Cyclic group over
All irreducible -representations of are 1-dimensional. If are distinct 1-dimensional characters, then any -equivariant map must be zero, because equivariance forces
for all , and choosing with implies . If , then .
Example 2: The standard 2D irreducible of
Let be the standard 2-dimensional irreducible representation of (e.g. the reflection representation on the plane of an equilateral triangle). Schur’s lemma over says any -equivariant must be of the form . So the commutant is exactly .
Example 3: A real irreducible where
Let act on by rotation by . This is an irreducible real representation. The real matrices commuting with a rotation are precisely the real linear combinations of and that rotation (equivalently, they identify with acting on ). Thus
illustrating the “division ring” conclusion over non-algebraically-closed fields.