Maschke's theorem
If char(k) does not divide |G|, then every finite-dimensional k-representation of a finite group is completely reducible.
Let be a finite group and a field. Consider finite-dimensional representations of over , equivalently finite-dimensional -modules.
Theorem (Maschke)
Assume that is invertible in (equivalently ). Then every finite-dimensional -representation of is semisimple: for every -subrepresentation , there exists a -stable subspace such that
as -representations (equivalently as -modules). In particular, every representation is completely reducible.
In module language: every finite-dimensional -module is a semisimple module.
Standard averaging proof (key construction)
Let be -stable. Choose any -linear projection (not necessarily -equivariant). Define the averaged map
Then:
- is -equivariant, i.e. a module homomorphism ,
- , so is a -equivariant projection,
- therefore is -stable and gives the complement .
This averaging step is exactly where the condition is used.
Remarks and consequences
- Over , Maschke always applies to finite groups, yielding complete reducibility over \u211a.
- The theorem is equivalent to semisimplicity of the group algebra (as a ring), and it underlies character theory (e.g. orthogonality of irreducible characters).
Examples
- A “good characteristic” decomposition for over . Let act on by permuting coordinates (a permutation representation). The 1-dimensional subspace is -stable (the trivial subrepresentation). Maschke guarantees an invariant complement, and indeed one isgiving , where is the 2-dimensional standard irreducible.
- A “good characteristic” example where not all irreducibles are 1D. Take over . Since , Maschke applies: every -module is semisimple. In particular, (the regular representation) decomposes as a direct sum of irreducibles, but over there is a 2-dimensional irreducible factor (because is irreducible over ). So semisimple does not mean “splits into 1-dimensional pieces”; it means “splits into irreducibles over the given field.”
- Failure in “bad characteristic”: over . Let and , so . Consider the 2-dimensional representation where acts by the unipotent matrix The line is -stable, but there is no -stable complement line: the only eigenvectors of lie in , so no other 1-dimensional subspace is preserved. Hence is not a direct sum of subrepresentations, and Maschke’s conclusion fails.