Suppose γ:[a,b]R\gamma:[a,b]\to\mathbb R is and f:[a,b]Rf:[a,b]\to\mathbb R is with respect to γ\gamma. If c[a,b]c\in[a,b], then the restrictions of ff and γ\gamma to the two subintervals are integrable in the same sense, and

abfdγ=acfdγ+cbfdγ.\int_a^b f\,d\gamma=\int_a^c f\,d\gamma+\int_c^b f\,d\gamma.

At an endpoint, the integral over the degenerate interval is defined to be zero.

Why the split works

For the mesh-limit definition used here, compare two fine on one subinterval while keeping the same fine partition on the other. The Cauchy criterion for the full integral implies the Cauchy criterion for each restricted integral. Combining fine partitions then gives the displayed sum. The cited reference states the increasing-integrator case using upper and ; its formulation should not be substituted for the mesh-limit definition without checking the integrator's discontinuities.

References
  • B. Yan, The Riemann–Stieltjes Integral, Theorem 6.9(c), pp. 6–7: course notes PDF.