Statement

Let f∈C∞(U×(0,T))f\in C^\infty(U\times(0,T)), T<∞T<\infty. Suppose every mixed derivative is uniformly bounded on K×(T−δK,T)K\times(T-\delta_K,T) for each compact K⊂UK\subset U, with some δK>0\delta_K>0. Then each ∂xα∂tjf\partial_x^\alpha\partial_t^j f has a locally uniform limit as t↑Tt\uparrow T. These limits form a compatible smooth : if Fj(x)=lim⁡t↑T∂tjf(x,t)F_j(x)=\lim_{t\uparrow T}\partial_t^jf(x,t), then

Fj∈C∞(U),∂xαFj=lim⁡t↑T∂xα∂tjf.F_j\in C^\infty(U),\qquad \partial_x^\alpha F_j=\lim_{t\uparrow T}\partial_x^\alpha\partial_t^jf.
Time Cauchy estimate and compatibility

A bound for ∂t(∂xα∂tjf)\partial_t(\partial_x^\alpha\partial_t^jf) gives a uniform Lipschitz estimate in time, hence the endpoint limit. On small rectangular boxes inside UU, the fundamental theorem of calculus along spatial coordinate segments identifies the spatial derivatives of each limit. Passing to the endpoint in the time identity gives

∂xα∂tjf(x,t)=∂xαFj(x)−∫tT∂xα∂tj+1f(x,s) ds.\partial_x^\alpha\partial_t^jf(x,t) =\partial_x^\alpha F_j(x)-\int_t^T\partial_x^\alpha\partial_t^{j+1}f(x,s)\,ds.

This records compatibility of consecutive normal derivatives. A bound for ff alone is insufficient, as a bounded oscillatory function near TT need not have a limit.