Statement

Let fC(U×(0,T))f\in C^\infty(U\times(0,T)), T<T<\infty. Suppose every mixed derivative is uniformly bounded on K×(TδK,T)K\times(T-\delta_K,T) for each compact KUK\subset U, with some δK>0\delta_K>0. Then each xαtjf\partial_x^\alpha\partial_t^j f has a locally uniform limit as tTt\uparrow T. These limits form a compatible smooth : if Fj(x)=limtTtjf(x,t)F_j(x)=\lim_{t\uparrow T}\partial_t^jf(x,t), then

FjC(U),xαFj=limtTxαtjf.F_j\in C^\infty(U),\qquad \partial_x^\alpha F_j=\lim_{t\uparrow T}\partial_x^\alpha\partial_t^jf.
Time Cauchy estimate and compatibility

A bound for t(xαtjf)\partial_t(\partial_x^\alpha\partial_t^jf) gives a uniform Lipschitz estimate in time, hence the endpoint limit. On small rectangular boxes inside UU, the fundamental theorem of calculus along spatial coordinate segments identifies the spatial derivatives of each limit. Passing to the endpoint in the time identity gives

xαtjf(x,t)=xαFj(x)tTxαtj+1f(x,s)ds.\partial_x^\alpha\partial_t^jf(x,t) =\partial_x^\alpha F_j(x)-\int_t^T\partial_x^\alpha\partial_t^{j+1}f(x,s)\,ds.

This records compatibility of consecutive normal derivatives. A bound for ff alone is insufficient, as a bounded oscillatory function near TT need not have a limit.