Let (K,d)(K,d) be a and let FC(K,R)\mathcal F\subseteq C(K,\mathbb R). If F\mathcal F is and , meaning

supfFf(x)<for every xK,\sup_{f\in\mathcal F}|f(x)|<\infty \quad\text{for every }x\in K,

then F\mathcal F is . Thus there is M<M<\infty such that

f(x)Mfor every fF and xK.|f(x)|\le M \quad\text{for every }f\in\mathcal F\text{ and }x\in K.
Remarks

This lemma is a standard step in the proof of the .