Alternating series test (Leibniz): Let (an)(a_n) be a sequence of real numbers such that

  1. an≥0a_n\ge 0 for all nn,
  2. (an)(a_n) is decreasing, and
  3. an→0a_n\to 0.

Then the ∑n=1∞(−1)n−1an\sum_{n=1}^\infty (-1)^{n-1}a_n .

Remarks

A common consequence is an error bound for : if ss is the limit and sN=∑n=1N(−1)n−1ans_N=\sum_{n=1}^N (-1)^{n-1}a_n, then ∣s−sN∣≤aN+1|s-s_N|\le a_{N+1}. This test is a basic source of and uses the necessary condition .