Statement

Let φ\varphi be a on a AA. Suppose (πφ,Hφ,ξφ)(\pi_\varphi,H_\varphi,\xi_\varphi) is the cyclic triple produced by the , and (ρ,K,η)(\rho,K,\eta) is any satisfying

φ(a)=ρ(a)η,η(aA).\varphi(a)=\langle\rho(a)\eta,\eta\rangle \qquad(a\in A).

Then there is a unique unitary U:HφKU:H_\varphi\to K such that

Uξφ=ηandUπφ(a)=ρ(a)U(aA).U\xi_\varphi=\eta \quad\text{and}\quad U\pi_\varphi(a)=\rho(a)U \qquad(a\in A).

Thus the pointed cyclic representation implementing φ\varphi is unique up to canonical . The uniqueness is pointed: both the representation and its distinguished cyclic vector are part of the data.

Construction of the unitary

On the dense cyclic subspace, define

U0(πφ(a)ξφ)=ρ(a)η.U_0\bigl(\pi_\varphi(a)\xi_\varphi\bigr)=\rho(a)\eta.

The implementing identities show that both sides have the same inner products:

πφ(a)ξφ,πφ(b)ξφ=φ(ba)=ρ(a)η,ρ(b)η.\langle\pi_\varphi(a)\xi_\varphi,\pi_\varphi(b)\xi_\varphi\rangle =\varphi(b^*a) =\langle\rho(a)\eta,\rho(b)\eta\rangle.

Hence U0U_0 is well defined and isometric. Cyclicity makes its range dense, so it extends to the asserted unitary. Density also proves uniqueness Murphy, Theorem 3.3.3.

Why the pointing matters

The theorem is stronger than unpointed unitary equivalence: the implementing unitary must carry the distinguished cyclic vector to the other distinguished vector. An unpointed cyclic representation may have many that induce different positive functionals. Likewise, dropping cyclicity permits extra orthogonal summands and destroys uniqueness.

References
  1. Gerard J. Murphy, C-Algebras and Operator Theory, Academic Press, 1990. DOI record. Relevant: §3.3, especially Theorem 3.3.3 on existence and uniqueness of the cyclic representation.
  2. Gert K. Pedersen, C-Algebras and Their Automorphism Groups, 2nd ed., Academic Press, 2018. DOI record. Relevant: Chapter 3 on positive functionals and cyclic representations.