A pushforward measure transports a measure along a measurable map. Let (X,A,μ)(X,\mathcal A,\mu) be a , let (Y,B)(Y,\mathcal B) be a , and let T:XYT:X\to Y be a . The pushforward of μ\mu by TT, denoted T#μT_\#\mu or TμT_*\mu, is the on (Y,B)(Y,\mathcal B) defined by

(T#μ)(B)=μ(T1(B))(BB).(T_\#\mu)(B)=\mu(T^{-1}(B))\qquad(B\in\mathcal B).

The definition measures subsets of YY by pulling them back to XX. Pushforwards are the natural language for the .

Examples
  • Let λ\lambda be Lebesgue measure on [0,1][0,1] and let T(x)=x2T(x)=x^2. Then ν=T#λ\nu=T_\#\lambda satisfies ν([0,t])=t\nu([0,t])=\sqrt t for 0t10\le t\le1, so ν\nu has density 1/(2y)1/(2\sqrt y) on (0,1](0,1].
  • If πX:X×YX\pi_X:X\times Y\to X is projection and μν\mu\otimes\nu is a with ν(Y)<\nu(Y)<\infty, then
    (πX)#(μν)(A)=(μν)(A×Y)=μ(A)ν(Y)(\pi_X)_\#(\mu\otimes\nu)(A)=(\mu\otimes\nu)(A\times Y)=\mu(A)\nu(Y)
    for AAA\in\mathcal A. Thus (πX)#(μν)=ν(Y)μ(\pi_X)_\#(\mu\otimes\nu)=\nu(Y)\mu; in particular, it equals μ\mu when ν\nu is a probability measure.