Continuity from above: Let (X,Σ,μ)(X,\Sigma,\mu) be a and let E1,E2,ΣE_1,E_2,\dots \in \Sigma satisfy

E1E2E3andμ(E1)<.E_1 \supseteq E_2 \supseteq E_3 \supseteq \cdots \quad\text{and}\quad \mu(E_1)<\infty.

Then

μ ⁣(n=1En)=limnμ(En).\mu\!\left(\bigcap_{n=1}^\infty E_n\right)=\lim_{n\to\infty}\mu(E_n).

This complements and is a basic limiting property of a that is used repeatedly in measure-theoretic arguments.