Statement

Let GG be a and let π:GU(H)\pi:G\to U(H) be a on a . The following conditions are equivalent:

  1. π\pi is ;
  2. every gπ(g)ξ,ηg\mapsto\langle\pi(g)\xi,\eta\rangle is continuous; and
  3. every diagonal coefficient gπ(g)ξ,ξg\mapsto\langle\pi(g)\xi,\xi\rangle is continuous.

In conditions 2 and 3, it is enough to require continuity at the identity. Thus weak operator continuity and strong operator continuity agree for unitary representations, even though the and differ on general operator families.

Proof mechanism

Strong continuity immediately implies coefficient continuity. Polarization recovers all coefficients from diagonal ones. Conversely, unitarity gives

π(g)ξξ2=2ξ22Reπ(g)ξ,ξ,\lVert\pi(g)\xi-\xi\rVert^2 =2\lVert\xi\rVert^2- 2\operatorname{Re}\langle\pi(g)\xi,\xi\rangle,

so continuity of the diagonal coefficient at the identity forces continuity of the there. Translation then gives continuity at every group element. This is the argument in Folland, opening of §3.1.

Why unitarity matters

The fixed norm π(g)ξ=ξ\lVert\pi(g)\xi\rVert=\lVert\xi\rVert turns weak convergence of an orbit to ξ\xi into norm convergence through the displayed identity. Without a uniform norm-preserving hypothesis, weak continuity of an operator-valued homomorphism need not imply strong continuity by this argument.

Conventions and scope

Here "weakly continuous" refers to continuity of every scalar matrix coefficient, not to of representations. No local compactness or finite-dimensionality assumption on GG or HH is needed.

References
  1. Gerald B. Folland, A Course in Abstract Harmonic Analysis, 2nd ed., CRC Press, 2016. DOI record. Relevant: the opening discussion of §3.1 on equivalent continuity conditions.