Let f:GHf:G\to H be a . Its K=ker(f)K=\ker(f) is a of GG, and ff induces a

fˉ:G/Kim(f),fˉ(gK)=f(g).\bar f:G/K\longrightarrow \operatorname{im}(f),\qquad \bar f(gK)=f(g).

In particular, if ff is surjective, then G/ker(f)HG/\ker(f)\cong H.

Remarks

This is the basic “quotient equals image” principle. With I=im(f)I=\operatorname{im}(f), it can be expressed by the

1KGI1.1\longrightarrow K\longrightarrow G\longrightarrow I\longrightarrow 1.