Theorem
Schur's lemma for unitary representations
An irreducible complex unitary representation has only scalar bounded operators in its commutant.
Statement
Let be a unitary representation of a group on a nonzero complex Hilbert space . Schur's lemma for unitary representations states that is irreducible if and only if every bounded operator satisfying
is a scalar multiple of the identity. Equivalently, the commutant equals . Here irreducibility means that has no nonzero proper closed invariant subspace. No finite-dimensionality, compactness, or local compactness hypothesis on is required.
Proof mechanism
If a closed subspace is invariant under a unitary representation, its orthogonal complement is invariant, so the corresponding orthogonal projection lies in the commutant. Conversely, for a self-adjoint operator in the commutant, every spectral projection also commutes with . Irreducibility forces all these projections to be or , hence the operator is scalar. Applying this to the real and imaginary parts of an arbitrary commutant element proves the theorem Folland, Theorem 3.5.
Intertwiners between irreducibles
Let and be irreducible unitary representations and let be a bounded intertwining operator from to . Then , or is a positive scalar multiple of a unitary intertwiner. Thus inequivalent irreducibles admit no nonzero bounded intertwiner; if , every such is scalar. This follows by applying the commutant statement to and .
Conventions and scope
References
- Gerald B. Folland, A Course in Abstract Harmonic Analysis, 2nd ed., CRC Press, 2016. DOI record. Relevant: §3.1, especially Theorem 3.5.
- Jacques Dixmier, -Algebras, North-Holland Mathematical Library 15, North-Holland, 1977. Publisher record. Relevant: Chapter 2 on representations and commutants.