Statement

Let GG be an with μ\mu, and give its G^\widehat G the μ^\widehat\mu. The Fourier inversion theorem states that if fL1(G,μ)f\in L^1(G,\mu) and its f^\widehat f belongs to L1(G^,μ^)L^1(\widehat G,\widehat\mu), then

f0(x)=G^f^(γ)γ(x)dμ^(γ)f_0(x)=\int_{\widehat G}\widehat f(\gamma)\gamma(x)\,d\widehat\mu(\gamma)

defines a continuous function vanishing at infinity, and f0=ff_0=f . The inverse integral converges absolutely for every xx and uses the fixed dual normalization. Hence f0(x)=f(x)f_0(x)=f(x) at every point when ff itself is continuous.

Why the hypotheses matter

The two L1L^1 assumptions make both transforms ordinary absolutely convergent integrals. Without integrability of f^\widehat f, inversion may still hold in L2L^2, by summability, or in the sense of distributions, but the displayed integral need not converge pointwise.

Relation to duality

Applying Fourier transformation on G^\widehat G and using the evaluation isomorphism GG^^G\cong\widehat{\widehat G} from the gives

f^^(x)=f(x)\widehat{\widehat f}(x)=f(-x)

in additive notation under the convention f^(γ)=Gf(x)γ(x)dμ(x)\widehat f(\gamma)=\int_Gf(x)\overline{\gamma(x)}\,d\mu(x). The reflection changes when the transform convention changes.

Standard examples

For G=RnG=\mathbb R^n, the theorem is Euclidean Fourier inversion with the constants determined by the exponential convention. For G=ZG=\mathbb Z, it reconstructs an absolutely summable sequence from its Fourier transform on the circle. On a compact abelian group, the dual is discrete and the inverse integral becomes a sum over characters.

References
  1. Walter Rudin, Fourier Analysis on Groups, Wiley-Interscience, 1962. Wiley DOI record. Relevant: Chapter 1, inversion and duality.
  2. Gerald B. Folland, A Course in Abstract Harmonic Analysis, 2nd ed., CRC Press, 2016. DOI record. Relevant: Chapter 4, Fourier inversion on locally compact abelian groups.