Definition
Direct integral of operators
A direct integral operator acts fiberwise by a measurable family of closed operators on a direct integral Hilbert space.
Definition
Let be a measurable field of Hilbert spaces over , and let be a measurable family of closed densely defined operators on the fibers. The direct integral
has domain consisting of measurable sections such that almost everywhere and is square-integrable; it acts by . Here measurability of the family can be expressed by measurability of the graph projections. Operators and families that agree almost everywhere define the same direct integral.
Bounded and unbounded cases
If the are bounded and , then is the bounded decomposable operator determined by the field. Without a uniform essential bound, the same formula usually defines an unbounded operator with the stated maximal natural domain. The graph of is the direct integral of the fiber graphs, so closedness passes from the fibers to .
Fiberwise spectral properties
Adjoints and standard operator properties are computed fiberwise under the measurability hypotheses:
In particular, is self-adjoint when is self-adjoint almost everywhere. Fiberwise functional calculus then gives
for bounded Borel . These results are part of the direct-integral operator theory in Takesaki, Chapter IV, §8.
Examples and scope
For one-dimensional fibers , the direct integral of scalar operators is the multiplication operator by the measurable function on , possibly unbounded. A bare family of closed operators need not be measurable and therefore need not define a direct integral.
References
- Masamichi Takesaki, Theory of Operator Algebras I, Springer, 1979. DOI record. Relevant: Chapter IV, §8, direct integrals and decomposable operators.
- Jacques Dixmier, Von Neumann Algebras, North-Holland, 1981. Publisher record. Relevant: Chapter II, measurable fields and direct integrals of operators.