Definition
Decomposable operator
A bounded operator on direct integrals that is given almost everywhere by a measurable essentially bounded field of fiber operators.
Definition
Let and be direct integrals of [[linear-algebra/hilbert-space|Hilbert spaces]]. A bounded operator is decomposable if there is a measurable field of bounded operators , with , such that
for almost every and every measurable square-integrable section . One writes . The field is determined up to equality almost everywhere, and .
Algebraic operations
Sums, products of composable decomposable operators, and adjoints are decomposable and are computed fiberwise:
almost everywhere. Consequently, decomposable operators on a fixed direct integral form a von Neumann algebra. Fiberwise properties such as self-adjointness, positivity, or unitarity pass to the global operator and back, modulo null sets.
Characterization by diagonal operators
For , let act diagonally by . Under the standard separability and -finiteness hypotheses used in direct-integral theory, the decomposable operators are precisely the bounded operators commuting with every . Thus decomposability is an intrinsic commutant condition, not a claim that the fibers are diagonalizable Takesaki, Chapter IV, §8.
Examples and scope
A diagonal multiplication operator is decomposable with . More generally, a measurable essentially bounded family of matrices defines a decomposable operator on a direct integral of finite-dimensional fibers. An operator that mixes values at different base points, such as translation on , is generally not decomposable over the usual position-space decomposition.
References
- Jacques Dixmier, Von Neumann Algebras, North-Holland, 1981. Publisher record. Relevant: Chapter II, §2 on decomposable operators.
- Masamichi Takesaki, Theory of Operator Algebras I, Springer, 1979. DOI record. Relevant: Chapter IV, §8 on direct integrals and decomposable operators.