Third Isomorphism Theorem (Groups). Let GG be a , and let N⊆KN\subseteq K be of GG. Then K/N⊴G/NK/N\trianglelefteq G/N, and there is a canonical isomorphism of

(G/N)/(K/N)≅G/K,(G/N)/(K/N) \cong G/K,

induced by gN↦gKgN\mapsto gK.

Remarks

The map G/N→G/KG/N\to G/K, gN↦gKgN\mapsto gK, is surjective with kernel K/NK/N, so the result follows from the .