Clausius theorem and entropy

For reversible cycles, the cyclic integral ∮ δQ_rev/T vanishes, implying the existence of entropy as a state function with dS = δQ_rev/T.
Clausius theorem and entropy

Statement

For a system undergoing a reversible cyclic process through equilibrium states, the Clausius integral satisfies

δQrevT=0. \oint \frac{\delta Q_{\mathrm{rev}}}{T} = 0.

Consequently, there exists a state function SS (the ) such that for any two equilibrium states A,BA,B and any reversible path γ\gamma from AA to BB,

S(B)S(A)=γδQrevT, S(B)-S(A) = \int_{\gamma} \frac{\delta Q_{\mathrm{rev}}}{T},

so the integral is path independent among reversible paths and defines SS up to an additive constant.

More generally, for an arbitrary (possibly irreversible) cyclic process,

δQT0, \oint \frac{\delta Q}{T} \le 0,

which is the .

Key hypotheses and conclusions

Hypotheses

Conclusions

  • The differential form δQrev/T\delta Q_{\mathrm{rev}}/T is an exact differential: dS=δQrev/TdS = \delta Q_{\mathrm{rev}}/T along reversible changes.
  • Entropy differences are intrinsic to the endpoints (state function property).
  • Irreversibility manifests as strict inequality in the cyclic Clausius integral and, equivalently, nonnegative entropy production.

Proof idea / significance

Idea (from Carnot cycles). Using , one shows that for reversible processes between fixed endpoint states, the quantity δQrev/T\int \delta Q_{\mathrm{rev}}/T is independent of the chosen reversible path. Path independence implies the existence of a state function whose differential along reversible paths is δQrev/T\delta Q_{\mathrm{rev}}/T. Extending to arbitrary cycles yields the inequality form.

Significance. Clausius’ theorem is the precise bridge from the operational second law (impossibility statements) to a new state function, entropy, which then organizes equilibrium thermodynamics, stability criteria, and the construction of thermodynamic potentials.