Euler relation for extensive thermodynamic potentials

For an extensive fundamental relation U(S,V,N), Euler’s theorem gives U = TS − pV + μN (and multicomponent variants).
Euler relation for extensive thermodynamic potentials

Statement

Let a be in and admit a differentiable fundamental relation for the of the form U=U(S,V,N)U=U(S,V,N), where S,V,NS,V,N are extensive variables.
Assume UU is extensive, i.e. homogeneous of degree 11:

U(λS,λV,λN)=λU(S,V,N)(λ>0). U(\lambda S,\lambda V,\lambda N)=\lambda\,U(S,V,N)\qquad(\lambda>0).

Define the intensive variables in the usual way:

T=(US)V,N,p=(UV)S,N,μ=(UN)S,V. T=\left(\frac{\partial U}{\partial S}\right)_{V,N},\qquad p=-\left(\frac{\partial U}{\partial V}\right)_{S,N},\qquad \mu=\left(\frac{\partial U}{\partial N}\right)_{S,V}.

Then the Euler relation holds:

U=TSpV+μN. U = TS - pV + \mu N.

More generally, for a multicomponent system with N=(N1,,Nr)N=(N_1,\dots,N_r) and chemical potentials μi\mu_i, one has

U=TSpV+i=1rμiNi. U = TS - pV + \sum_{i=1}^r \mu_i N_i.

Key hypotheses

  • A well-defined in equilibrium with differentiable U(S,V,N)U(S,V,N).
  • Extensivity (first-order homogeneity) of UU in the extensive variables.
  • Standard identifications of T,p,μT,p,\mu as partial derivatives (see , , ).

Conclusions

  • The internal energy decomposes into intensive–extensive pairings: U=TSpV+μNU=TS-pV+\mu N (or the multicomponent sum).
  • Differentiating the Euler relation and comparing with the yields the .

Proof idea / significance

This is an application of Euler’s theorem for homogeneous functions: if UU is differentiable and homogeneous of degree 11, then

U=SUS+VUV+NUN. U = S\frac{\partial U}{\partial S}+V\frac{\partial U}{\partial V}+N\frac{\partial U}{\partial N}.

Substituting the thermodynamic identifications of the derivatives gives U=TSpV+μNU=TS-pV+\mu N. Conceptually, the theorem encodes extensivity (scaling with system size) and is the starting point for intensive-variable constraints (Gibbs–Duhem) and for between thermodynamic potentials.