Uniform limit theorem. Let XX be a and YY a . If fn:XYf_n:X\to Y are and fnff_n\to f , then f:XYf:X\to Y is continuous. Uniform convergence means that for every ε>0\varepsilon>0 there exists NN such that

nNdY(fn(x),f(x))<εfor every xX.n\ge N\quad\Longrightarrow\quad d_Y\bigl(f_n(x),f(x)\bigr)<\varepsilon \quad\text{for every }x\in X.
Counterexample for pointwise convergence

fn(x)=xnf_n(x) = x^n on [0,1][0, 1] converges pointwise to a discontinuous limit:

f(x)={0x[0,1)1x=1.f(x) = \begin{cases} 0 & x \in [0,1) \\ 1 & x = 1 \end{cases}.

The convergence is not uniform.