Statement

Let HH be a and let AB(H)A\subseteq B(H) be a unital self-adjoint subalgebra. The von Neumann bicommutant theorem states that

ASOT=AWOT=A,\overline A^{\,\mathrm{SOT}} =\overline A^{\,\mathrm{WOT}} =A'',

where the closures use the and , and AA'' is the of AA. Consequently, such an algebra is a exactly when it equals its bicommutant. The result concerns operator topologies, not operator-norm closure.

Why the closures agree

Commutants are weak-operator closed, so both operator-topology closures of AA lie in AA''. For the converse, fix ξH\xi\in H. The orthogonal projection onto Aξ\overline{A\xi} belongs to AA'. This makes it possible to approximate TξT\xi by vectors aξa\xi, with aAa\in A, for every TAT\in A''. Applying the same argument to finite direct sums of HH simultaneously approximates TT on any finite set of vectors, which is exactly strong-operator approximation Kadison–Ringrose, Theorem 5.3.1.

Hypotheses and consequences

Unitality and closure under adjoints are essential to the stated form. A non-self-adjoint operator algebra can equal neither its weak closure nor the self-adjoint algebra suggested by a bicommutant. The theorem also shows that the generated by a unital self-adjoint algebra AA can be described without choosing between strong closure, weak closure, or double commutation.

References
  1. Richard V. Kadison and John R. Ringrose, Fundamentals of the Theory of Operator Algebras, Volume I: Elementary Theory, American Mathematical Society, 1997. AMS DOI record. Relevant: Theorem 5.3.1 and the surrounding discussion of operator topologies.
  2. Jacques Dixmier, Von Neumann Algebras, North-Holland, 1981. Publisher record. Relevant: Chapter I on commutants and the density theorem.