Statement

Let 1≤p0,p1≤∞1\le p_0,p_1\le\infty, 0≤θ≤10\le\theta\le1, and

1p=1−θp0+θp1.\frac1p=\frac{1-\theta}{p_0}+\frac{\theta}{p_1}.

For f∈Lp0∩Lp1f\in L^{p_0}\cap L^{p_1}, the Lebesgue interpolation inequality is

∥f∥p≤∥f∥p01−θ∥f∥p1θ.\|f\|_p\le\|f\|_{p_0}^{1-\theta}\|f\|_{p_1}^{\theta}.
Direct proof

For finite distinct endpoints and 0<θ<10<\theta<1, apply to ∣f∣p(1−θ)∣f∣pθ|f|^{p(1-\theta)}|f|^{p\theta}, with conjugate exponents p0/[p(1−θ)]p_0/[p(1-\theta)] and p1/(pθ)p_1/(p\theta). If an endpoint is infinity, bound its factor by the essential supremum. Coincident endpoints and θ=0,1\theta=0,1 give equality. This is an estimate for one function, distinct from an operator interpolation theorem.