For a square AA, its matrix exponential is

eA=n=0Ann!.e^A=\sum_{n=0}^\infty\frac{A^n}{n!}.

The operator norm bounds this series by eAe^{\|A\|}, proving absolute convergence. The same definition works for a bounded operator on a Banach space.

Constant-coefficient evolution

Termwise differentiation gives ddtetA=AetA=etAA\frac{d}{dt}e^{tA}=Ae^{tA}=e^{tA}A, so e(ts)Ae^{(t-s)A} is the propagator of y=Ayy'=Ay. Also etAesA=e(t+s)Ae^{tA}e^{sA}=e^{(t+s)A}, hence etAe^{tA} is invertible. For distinct matrices, eA+B=eAeBe^{A+B}=e^Ae^B is guaranteed when AB=BAAB=BA and is false in general without a commutation hypothesis.