Spin group

A simply connected double cover of $SO(n)$ defined inside the Clifford algebra.
Spin group

Definition (via the Clifford algebra)

Let V=RnV=\mathbb R^n with its standard inner product ,\langle\cdot,\cdot\rangle, and let Cl(V)\mathrm{Cl}(V) be the real Clifford algebra generated by VV subject to the relations

vv=v,v1(vV). v\cdot v=-\langle v,v\rangle\,1 \quad (v\in V).

The spin group Spin(n)\mathrm{Spin}(n) is the subgroup of the even Clifford algebra Cl0(V)\mathrm{Cl}^0(V) generated by products of an even number of unit vectors:

Spin(n)=v1v2v2kviV, vi,vi=1Cl0(V)×. \mathrm{Spin}(n)=\langle v_1v_2\cdots v_{2k}\mid v_i\in V,\ \langle v_i,v_i\rangle=1\rangle \subset \mathrm{Cl}^0(V)^\times.

Covering map to SO(n)SO(n)

There is a canonical group homomorphism

ρ:Spin(n)SO(n) \rho:\mathrm{Spin}(n)\to SO(n)

defined by the conjugation action on VCl(V)V\subset \mathrm{Cl}(V):

ρ(s)(v)=svs1. \rho(s)(v)=s\,v\,s^{-1}.

One checks that ρ(s)\rho(s) preserves ,\langle\cdot,\cdot\rangle and has determinant 11, hence lands in the . Moreover,

ker(ρ)={±1}, \ker(\rho)=\{\pm 1\},

so ρ\rho is a 22-fold covering map. For n3n\ge 3, Spin(n)\mathrm{Spin}(n) is connected and simply connected, and ρ\rho identifies it as the of SO(n)SO(n).

Lie algebra and context

The differential dρed\rho_e is an isomorphism of Lie algebras, so the Lie algebra of Spin(n)\mathrm{Spin}(n) is canonically identified with the . This makes Spin(n)\mathrm{Spin}(n) fundamental in topology and representation theory: “spin representations” are representations of Spin(n)\mathrm{Spin}(n) that do not descend to SO(n)SO(n), reflecting the nontriviality of the covering.