Let GG be a with Lie algebra g=Lie(G)\mathfrak g=\operatorname{Lie}(G).

Theorem (subgroup–subalgebra correspondence)
  1. If HGH\subseteq G is a connected , then Lie(H)\operatorname{Lie}(H) is a of g\mathfrak g (by ).
  1. Conversely, for every Lie subalgebra hg\mathfrak h\subseteq \mathfrak g there exists a unique connected immersed Lie subgroup HGH\subseteq G such that
Lie(H)=h.\operatorname{Lie}(H)=\mathfrak h.

This subgroup is often denoted H=exp(h)H=\langle \exp(\mathfrak h)\rangle, emphasizing that it is generated by exponentials of elements of h\mathfrak h via the .

  1. The immersed subgroup HH is embedded if and only if it is closed in GG; this is where becomes decisive.
Motivation

This correspondence packages the idea that “connected subgroups are determined infinitesimally.” One often uses it in the form: a Lie subalgebra h\mathfrak h determines a unique connected subgroup, and computations can be done in h\mathfrak h using the bracket before passing back to HH (compare ).

It is also a key input in global existence results such as , which asserts that every finite-dimensional Lie algebra integrates to a Lie group.