Example: the sphere as a homogeneous space

The -sphere is a homogeneous space via the standard transitive action.
Example: the sphere as a homogeneous space

Consider the standard action of on Rn+1\mathbb R^{n+1}, hence on the unit sphere

Sn={xRn+1:x=1}. S^n=\{x\in\mathbb R^{n+1}:\|x\|=1\}.

This is a smooth .

Transitivity and stabilizer (explicit)

Fix the “north pole” p=en+1=(0,,0,1)p=e_{n+1}=(0,\dots,0,1). For any xSnx\in S^n, there exists gSO(n+1)g\in SO(n{+}1) with gp=xg\cdot p=x (choose an orthonormal basis sending en+1e_{n+1} to xx), so the action is .

The stabilizer of pp consists of rotations preserving the orthogonal complement pRnp^\perp\cong\mathbb R^n, hence

Stab(p)SO(n), \mathrm{Stab}(p)\cong SO(n),

as an embedded (see ).

Identification with a coset space

Define

Φ:SO(n+1)/SO(n)Sn,Φ(gSO(n)):=gp. \Phi: SO(n{+}1)/SO(n) \longrightarrow S^n,\qquad \Phi(g\,SO(n)):=g\cdot p.

This is well-defined because elements of SO(n)SO(n) fix pp. It is bijective by transitivity and the stabilizer description, and it is a diffeomorphism once we use the standard smooth structure on the SO(n+1)/SO(n)SO(n{+}1)/SO(n) (which exists because SO(n)SO(n) is closed; compare the ). Thus

SnSO(n+1)/SO(n) S^n \cong SO(n{+}1)/SO(n)

as a .

Dimension check (concrete calculation)

Using dimSO(m)=m(m1)2\dim SO(m)=\frac{m(m-1)}{2},

dim(SO(n+1)/SO(n))=(n+1)n2n(n1)2=n=dimSn, \dim\bigl(SO(n{+}1)/SO(n)\bigr) =\frac{(n{+}1)n}{2}-\frac{n(n-1)}{2}=n=\dim S^n,

consistent with the identification.

Special case. For n=2n=2, this reads S2SO(3)/SO(2)S^2\cong SO(3)/SO(2), connecting directly to .