Statement

Suppose T=cI+p.v.⁡KT=cI+\operatorname{p.v.}K is a singular integral with ∣K(x,y)∣≤C∣x−y∣−n|K(x,y)|\le C|x-y|^{-n}, and let aa be bounded and Lipschitz. For compactly supported smooth ff, its with multiplication is

[Ma,T]f(x)=a(x)Tf(x)−T(af)(x)=∫(a(x)−a(y))K(x,y)f(y) dy.[M_a,T]f(x)=a(x)Tf(x)-T(af)(x) =\int(a(x)-a(y))K(x,y)f(y)\,dy.

The integral is absolutely convergent, and the local term cIcI cancels.

Gain at the diagonal

Lipschitz continuity gives ∣a(x)−a(y)∣≤Ca∣x−y∣|a(x)-a(y)|\le C_a|x-y|, so the new kernel is bounded by CCa∣x−y∣1−nC C_a|x-y|^{1-n} near the diagonal, an integrable singularity. Boundedness of aa controls the remaining region. The identity follows first for truncated integrals and then by dominated convergence.