Statement

Every TT extends uniquely from L2LpL^2\cap L^p to a bounded operator on Lp(Rn)L^p(\mathbb R^n) for 1<p<1<p<\infty, with

TfpCpfp.\|Tf\|_p\le C_p\|f\|_p.

The constant depends on dimension, pp, the kernel size and regularity bounds, its Hölder exponent, and the L2L^2 operator norm.

Proof mechanism and endpoints

The Calderón–Zygmund decomposition splits an integrable input into a bounded part and localized pieces of mean zero. The L2L^2 bound handles the bounded part; cancellation and kernel regularity control the others off enlarged supporting cubes. This gives the distribution-function estimate {Tf>λ}Cf1/λ|\{|Tf|>\lambda\}|\le C\|f\|_1/\lambda. Interpolation gives 1<p<21<p<2, and applying the same argument to the adjoint and using duality gives 2<p<2<p<\infty. The cited lecture notes supply the full decomposition and interpolation proof.

Neither strong L1L^1 nor strong LL^\infty boundedness is part of this conclusion.

References