For a differentiable velocity field, the rate-of-strain tensor is the symmetric matrix

D(u)=12(u+(u)T),D(u)ij=12(jui+iuj).D(u)=\frac12\bigl(\nabla u+(\nabla u)^{\mathsf T}\bigr), \qquad D(u)_{ij}=\frac12(\partial_j u_i+\partial_i u_j).

Here u\nabla u denotes the , with (u)ij=jui(\nabla u)_{ij}=\partial_j u_i.

Infinitesimal deformation

If two nearby particles have infinitesimal separation ξ\xi, then ξ˙=(u)ξ\dot\xi=(\nabla u)\xi and

ddtξ2=2ξTD(u)ξ.\frac{d}{dt}|\xi|^2=2\xi^{\mathsf T}D(u)\xi.

The skew-symmetric part of the gradient contributes local rotation but not this change in squared length. Incompressibility implies trD(u)=0\operatorname{tr}D(u)=0.

References