Fiber of a map

The preimage of a point under a map, viewed as a subset of the domain.
Fiber of a map

Let f:XYf : X \to Y be a map and let yYy \in Y.

Definition

The fiber of ff over yy (also called the preimage fiber) is the subset

f1(y)={xXf(x)=y}X. f^{-1}(y)=\{x\in X \mid f(x)=y\}\subseteq X.

When f:MNf : M \to N is a between , the fiber f1(y)f^{-1}(y) is a distinguished subset of MM whose geometry depends strongly on whether yy is a . In particular, if yy is a regular value then f1(y)f^{-1}(y) is a smooth submanifold of MM; if ff is a then every yNy\in N is regular and all fibers are smooth submanifolds of the same dimension.

Examples

  1. Projection fibers. For the projection πM:M×FM\pi_M : M\times F \to M, the fiber over mMm\in M is

    πM1(m)={m}×F. \pi_M^{-1}(m)=\{m\}\times F.
  2. Level sets of a function. For f:R2Rf:\mathbb{R}^2\to \mathbb{R} given by f(x,y)=x2+y2f(x,y)=x^2+y^2, the fibers are the level sets:

    • if r>0r>0, then f1(r)={(x,y):x2+y2=r}f^{-1}(r)=\{(x,y):x^2+y^2=r\}, a circle of radius r\sqrt r;
    • if r=0r=0, then f1(0)={(0,0)}f^{-1}(0)=\{(0,0)\}, a single point.
  3. A fiber with multiple components. Let h:S1Rh:S^1\to \mathbb{R} be the height function h(cost,sint)=sinth(\cos t,\sin t)=\sin t. Then the fiber over 00 is

    h1(0)={(1,0),(1,0)}, h^{-1}(0)=\{(1,0),(-1,0)\},

    which has two connected components.