Atiyah sequence

The short exact sequence 0 to ad(P) to TP/G to TM to 0 associated to a principal bundle.
Atiyah sequence

Let π:PM\pi:P\to M be a principal GG-bundle with Lie algebra g\mathfrak{g}. Its is A(P)=TP/GMA(P)=TP/G\to M, equipped with the anchor a:A(P)TMa:A(P)\to TM induced by dπd\pi.

Define the adjoint bundle ad(P)=P×AdgM\mathrm{ad}(P)=P\times_{\mathrm{Ad}}\mathfrak{g}\to M. There is a natural injection

ι:ad(P)TP/G \iota:\mathrm{ad}(P)\hookrightarrow TP/G

defined fiberwise by sending [p,X]ad(P)x[p,X]\in \mathrm{ad}(P)_x to the class of the fundamental vertical vector Xp#TpPX^\#_p\in T_pP. The anchor aa is surjective, and its kernel is exactly the image of ι\iota. Thus one obtains the Atiyah sequence of vector bundles over MM:

0ad(P) ι TP/G a TM0. 0 \longrightarrow \mathrm{ad}(P) \xrightarrow{\ \iota\ } TP/G \xrightarrow{\ a\ } \, TM \longrightarrow 0.

Exactness means:

  • ι\iota is injective,
  • aι=0a\circ \iota=0,
  • ker(a)=im(ι)\ker(a)=\mathrm{im}(\iota),
  • aa is surjective.

Examples

  1. Trivial bundle. If P=M×GP=M\times G, then TP/GTM(M×g)TP/G\cong TM\oplus (M\times\mathfrak{g}), ad(P)M×g\mathrm{ad}(P)\cong M\times \mathfrak{g}, and the sequence is

    0M×gTM(M×g)TM0, 0\to M\times\mathfrak{g}\to TM\oplus(M\times\mathfrak{g})\to TM\to 0,

    split by the obvious projection.

  2. Bundle over a point. For P=G{}P=G\to\{\ast\}, the sequence becomes 0g=g00\to \mathfrak{g}\xrightarrow{=}\mathfrak{g}\to 0.

  3. Circle bundles. For a principal U(1)U(1)-bundle, ad(P)M×iR\mathrm{ad}(P)\cong M\times i\mathbb{R} is a trivial line bundle, and the sequence exhibits TP/U(1)TP/U(1) as an extension of TMTM by this line.