Statement

Let U(t,s)U(t,s) be the of z′=A(t)zz'=A(t)z, and let d(t)d(t) be a continuous scalar. The propagator for z′=(A(t)−d(t)I)zz'=(A(t)-d(t)I)z is

V(t,s)=exp⁡(−∫std(r) dr)U(t,s).V(t,s)=\exp\left(-\int_s^t d(r)\,dr\right)U(t,s).

Differentiating this product proves the identity and the initial condition V(s,s)=IV(s,s)=I. No commutation between A(t)A(t) at different times is needed, because the damping factor is scalar.

Harmonics

If VmV_m corresponds to A−m2dIA-m^2dI, then

Vm(t,s)=exp⁡(−(m2−1)∫std(r) dr)V1(t,s).V_m(t,s)=\exp\left(-(m^2-1)\int_s^t d(r)\,dr\right)V_1(t,s).

For d≥0d\ge0, t≥st\ge s, and ∣m∣≥1|m|\ge1, higher harmonics have no larger propagator norm than the first harmonic under this comparison.