Let XX be a and let ΩX\Omega\subseteq X be with nonempty . Then its equals its topological interior:

core(Ω)=int(Ω).\operatorname{core}(\Omega)=\operatorname{int}(\Omega).
Proof idea

The inclusion int(Ω)core(Ω)\operatorname{int}(\Omega)\subseteq\operatorname{core}(\Omega) is direct. For the reverse inclusion, translate so that 0int(Ω)0\in\operatorname{int}(\Omega) and use convexity together with .