Let XX be a and let Ω⊆X\Omega\subseteq X be with nonempty . Then its equals its topological interior:

core⁡(Ω)=int⁡(Ω).\operatorname{core}(\Omega)=\operatorname{int}(\Omega).
Proof idea

The inclusion int⁡(Ω)⊆core⁡(Ω)\operatorname{int}(\Omega)\subseteq\operatorname{core}(\Omega) is direct. For the reverse inclusion, translate so that 0∈int⁡(Ω)0\in\operatorname{int}(\Omega) and use convexity together with .