Let XX be a and let ΩX\Omega\subset X be with 0int(Ω)0\in\operatorname{int}(\Omega) (see ).

Corollary: The pΩp_\Omega is continuous. Moreover,

int(Ω)={xXpΩ(x)<1}\operatorname{int}(\Omega)=\{x\in X\mid p_\Omega(x)<1\}

and

Ω={xXpΩ(x)1}.\overline{\Omega}=\{x\in X\mid p_\Omega(x)\le 1\}.

Here Ω\overline{\Omega} denotes the of Ω\Omega.

Remarks

Context: Continuity comes from the inclusion of a norm ball into Ω\Omega (since 0int(Ω)0\in\operatorname{int}(\Omega)), yielding a Lipschitz bound for pΩp_\Omega. The set identities combine with .