The zero-product Jordan algebra on C1\mathbb C^{1} is the C1\mathbb C^{1}, with its usual addition and scalar multiplication, and with

x∘y=0for all x,y∈C1.x\circ y=0\qquad\text{for all }x,y\in \mathbb C^{1}.

This bilinear commutative product satisfies the because both sides are zero. Its dimension over C\mathbb C is 11.

No unit

The vector space has a nonzero vector xx, whereas e∘x=0e\circ x=0 for every ee. Thus no element acts as a multiplicative unit. This is an object of over the stated field, but is not an object of either or . Positivity of the dimension matters: the zero-dimensional algebra is outside this family.

Complete endomorphism and automorphism descriptions

Every C\mathbb C-linear map TT preserves the product, since

T(x∘y)=T(0)=0=T(x)∘T(y).T(x\circ y)=T(0)=0=T(x)\circ T(y).

Conversely, a over C\mathbb C is required to be C\mathbb C-linear. Therefore, in JordC\mathbf{Jord}_{C},

End⁡(C1,0)=M1(C),Aut⁡(C1,0)=GL⁡1(C).\operatorname{End}(\mathbb C^{1},0)=M_{1}(\mathbb C), \qquad \operatorname{Aut}(\mathbb C^{1},0)=\operatorname{GL}_{1}(\mathbb C).

These identifications use the standard coordinate basis. On endomorphisms, composition becomes ordinary matrix multiplication and pointwise addition gives the matrix algebra. On automorphisms, composition gives the . Invertibility is sufficient because the inverse of an invertible also preserves the zero product.

The resulting has its ordinary associative product, and is a different object from this zero-product Jordan algebra.

Restricting the scalar field

As a real Jordan algebra this object has dimension 22, still with zero product. The same proof gives real-linear endomorphism algebra M2(R)M_{2}(\mathbb R) and GL⁡2(R)\operatorname{GL}_{2}(\mathbb R), after choosing the real basis obtained from the complex coordinate basis and its multiples by ii. These are larger collections of maps than the complex-linear ones. For example, coordinatewise complex conjugation is a real-linear automorphism but is not complex-linear.