Sylow's Third Theorem. Let GG be a finite with ∣G∣=pam|G| = p^{a}m where pp is prime and p∤mp\nmid m. Let npn_p denote the number of of GG. Then:

  1. np∣mn_p \mid m, and
  2. np≡1(modp)n_p \equiv 1 \pmod p.
Remarks

This theorem is a counting consequence of together with the and the on the set of Sylow pp-subgroups.