Proposition (Prime order implies cyclic). Let GG be a finite with ∣G∣=p|G|=p where pp is prime. Then GG is cyclic; more precisely, for every g∈Gg\in G with g≠eg\neq e, one has G=⟨g⟩G=\langle g\rangle.

Remarks

Context. This is one of the first applications of : subgroup orders must divide the group order.