Frattini Argument: Let GG be a finite , let NGN\trianglelefteq G be a , and let PP be a of NN (so pp divides N|N|). Let NG(P)N_G(P) denote the of PP in GG. Then

G=NNG(P).G = N\,N_G(P).
Equivalent characterizations

Equivalently, every gGg\in G can be written as g=nng=nn' with nNn\in N and nNG(P)n'\in N_G(P).