Proposition (finite cyclic groups). Let GG be a . Suppose G=gG=\langle g\rangle is cyclic of finite order nn. Then GG is to the additive group Z/nZ\mathbb Z/n\mathbb Z. Concretely, the chosen generator gg determines the isomorphism

φ:Z/nZG,φ(k)=gk\varphi:\mathbb Z/n\mathbb Z \longrightarrow G,\qquad \varphi(\overline{k})=g^k

is a well-defined isomorphism.

Remarks

This identifies finite cyclic groups up to isomorphism by their order. The displayed isomorphism is not canonical: it depends on the choice of generator gg.