Automorphisms of a cyclic group

Aut(C_n) is naturally isomorphic to (ℤ/nℤ)×
Automorphisms of a cyclic group

Proposition (Automorphism group of a finite cyclic group). Let GG be a cyclic group of order nn, and identify GZ/nZG\cong \mathbb Z/n\mathbb Z via . Then

Aut(G)  (Z/nZ)×, \mathrm{Aut}(G)\ \cong\ (\mathbb Z/n\mathbb Z)^\times,

where (Z/nZ)×(\mathbb Z/n\mathbb Z)^\times denotes the of the ring Z/nZ\mathbb Z/n\mathbb Z.

Equivalently: if G=gG=\langle g\rangle, then every automorphism αAut(G)\alpha\in \mathrm{Aut}(G) is uniquely determined by α(g)=gk\alpha(g)=g^k with gcd(k,n)=1\gcd(k,n)=1, and composition corresponds to multiplication of kk modulo nn.

Context. This makes automorphisms of cyclic groups completely explicit: an automorphism is exactly the choice of a generator-image. The group Aut(G)\mathrm{Aut}(G) itself is a central object in extension theory and semidirect products.